📏 trigonometry
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Phase Shift
1. **State the problem:** We want to find the formula for a trigonometric function of the form
$$h(x) = a \cos(bx + c) + d$$
Pole Height
1. We are given a vertical pole casting a shadow of 1.8 meters when the sun's elevation angle is 63.5 degrees. We need to find the height of the pole.
2. The problem can be solved
Airplane Angles
1. **Problem Statement:**
Two signposts A and B are 11 km apart on a straight highway. An airplane is flying above the highway. The angles of depression from the airplane to A and
Cosine Ratio
1. The problem is to understand the terms 'cahsign' which likely refers to 'cosine, adjacent, hypotenuse sign,' a mnemonic for trigonometric ratios.
2. The cosine of an angle in a
Value Tan
1. The problem is to find the value of $ (1 + \tan A)(1 + \tan B)$ where $A = 40^\circ$ and $B = 5^\circ$.
2. Substitute the given values:
Trig Ratio Simplify
1. The problem involves two expressions:\n$$\frac{1}{1} + \frac{1}{\text{something}} = 1$$\nand\n$$\frac{1 + \sin^2 A}{1 + \csc^2 A}$$\nWe need to analyze and simplify these.\n\n2.
Trig Angles Points
1. **Problem statement:** Given $\sin \alpha = \frac{3}{5}$ with $\alpha$ in the first quadrant, find:
- 5.3.1 $\tan \alpha$
Trig Identities
1. Problem 5.1: Simplify $$\sin(90^\circ - x) \cdot \cos(180^\circ + x) + \tan x \cdot \cos x \cdot \sin(x - 180^\circ)$$
Step 1: Use angle identities:
Pole Elevation
1. The problem states that Pushkar observes the top of a pole $23^3$ m high with an angle of elevation of $30^\circ$, and the distance between Pushkar and the pole is 66 m.
2. Firs
Pole Angle
1. **State the problem:** Pushkar observes the top of a pole that is $23^3$ meters high. The angle of elevation from Pushkar to the top of the pole is $30^\circ$, and the horizonta
Trig Intervals
1. დავიწყოთ პირველით:
თუ $\sin x = \frac{\sqrt{2}}{2}$ და $x\in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$, მაშინ $x$ არის ის კუთხე, რომლის სინი არის $\frac{\sqrt{2}}{2}$. პოპულარ
Trig Equations Intervals
1. Given $\sin x = \frac{\sqrt{2}}{2}$ and $x \in [-\frac{\pi}{2}, \frac{\pi}{2}]$, recognize that $\sin \frac{\pi}{4} = \frac{\sqrt{2}}{2}$. Since $\frac{\pi}{4}$ is within the in
Tan Half Angle Product
1. **State the problem:** Show that $$\tan\left(\frac{45^\circ + \theta}{2}\right) \cdot \tan\left(\frac{45^\circ - \theta}{2}\right) = \frac{\sqrt{2} \cos \theta - 1}{\sqrt{2} \co
Trig Solve Convert
1. **Resolve a equação trigonométrica** $5\sin x - 6\cos x - 5 = 0$.\n
Podemos reorganizar para isolar as funções trigonométricas:\n
Cosine Sine Form
1. State the problem: Express $3\cos \theta - 4\sin \theta$ in the form $R\cos(\theta - \alpha)$ and solve the equation $3\cos \theta - 4\sin \theta = 0$ for $0 \leq \theta \leq 2\
Angle Quadrants
1. Let's start by understanding the quadrants. The first quadrant is where angles measure from $0^\circ$ to $90^\circ$, and the fourth quadrant is where angles measure from $270^\c
Trigonometric Proof
1. We are given that \(\tan(x) = \csc(x) - \sin(x)\) and need to prove that \(\tan(x^2)\left(\frac{x}{2}\right) = -2 + \sqrt{5}\).\n\n2. Start by expressing \(\csc(x)\) in terms of
Cosine Positive Quadrants
1. The problem asks why the cosine function is positive in the first and fourth quadrants of the unit circle.
2. Recall that cosine of an angle $\theta$ in the unit circle is the $
Cosine Double Angle
1. **State the problem:**
We need to find all angles $x$ between 0 and 360 degrees such that $$\cos(2x) = \frac{\sqrt{3}}{2}.$$
Trigonometric Applications
1. The problem asks for three common applications of trigonometric identities and how to create steps to prove these identities using a flowchart.
2. Three common applications of t
Tan Product
1. **State the problem:** Prove that if $A = \frac{\pi}{12}$, then $$\tan A \cdot \tan 3A \cdot \tan 5A \cdot \tan 7A \cdot \tan 11A = 1.$$\n\n2. **Substitute $A = \frac{\pi}{12}$: