Pole Angle
1. **State the problem:** Pushkar observes the top of a pole that is $23^3$ meters high. The angle of elevation from Pushkar to the top of the pole is $30^\circ$, and the horizontal distance from Pushkar to the pole is 66 meters.
2. **Understand the problem:** We have a right triangle where:
- The height (opposite side) is the pole's height $h = 23^3$ m.
- The horizontal distance (adjacent side) between Pushkar and the pole base is 66 m.
- The angle of elevation is $30^\circ$.
3. **Calculate the actual height:** First, calculate $23^3$:
$$23^3 = 23 \times 23 \times 23 = 529 \times 23 = 12167.$$
So the pole height $h = 12167$ m.
4. **Verify the angle of elevation:** Using the tangent function:
$$\tan(30^\circ) = \frac{\text{height}}{\text{distance}} = \frac{12167}{66} \approx 184.35.$$
However, since $\tan(30^\circ) = \frac{1}{\sqrt{3}} \approx 0.577$, the given height and distance don't match the 30° angle.
5. **Reinterpret problem or check the meaning:** Possibly the height is $23^3$ meters written incorrectly or misunderstood. For the given distance (66 m) and angle ($30^\circ$), the height should be:
$$h = 66 \times \tan(30^\circ) = 66 \times \frac{1}{\sqrt{3}} \approx 38.11 \text{ m}.$$
6. **Conclusion:** Either the pole height or the problem data might be inconsistent. If it's to calculate the height using $30^\circ$ and 66 m distance, the height is about 38.11 m.
Since drawing a figure is requested, the triangle has:
- Horizontal side: 66 m
- Vertical side: $38.11$ m
- Angle at Pushkar: $30^\circ$
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**Final answer: The height of the pole according to the angle and distance is approximately $38.11$ meters.**