Subjects trigonometry

Pole Angle

Step-by-step solutions with LaTeX - clean, fast, and student-friendly.

Search Solutions

Pole Angle


1. **State the problem:** Pushkar observes the top of a pole that is $23^3$ meters high. The angle of elevation from Pushkar to the top of the pole is $30^\circ$, and the horizontal distance from Pushkar to the pole is 66 meters. 2. **Understand the problem:** We have a right triangle where: - The height (opposite side) is the pole's height $h = 23^3$ m. - The horizontal distance (adjacent side) between Pushkar and the pole base is 66 m. - The angle of elevation is $30^\circ$. 3. **Calculate the actual height:** First, calculate $23^3$: $$23^3 = 23 \times 23 \times 23 = 529 \times 23 = 12167.$$ So the pole height $h = 12167$ m. 4. **Verify the angle of elevation:** Using the tangent function: $$\tan(30^\circ) = \frac{\text{height}}{\text{distance}} = \frac{12167}{66} \approx 184.35.$$ However, since $\tan(30^\circ) = \frac{1}{\sqrt{3}} \approx 0.577$, the given height and distance don't match the 30° angle. 5. **Reinterpret problem or check the meaning:** Possibly the height is $23^3$ meters written incorrectly or misunderstood. For the given distance (66 m) and angle ($30^\circ$), the height should be: $$h = 66 \times \tan(30^\circ) = 66 \times \frac{1}{\sqrt{3}} \approx 38.11 \text{ m}.$$ 6. **Conclusion:** Either the pole height or the problem data might be inconsistent. If it's to calculate the height using $30^\circ$ and 66 m distance, the height is about 38.11 m. Since drawing a figure is requested, the triangle has: - Horizontal side: 66 m - Vertical side: $38.11$ m - Angle at Pushkar: $30^\circ$ --- **Final answer: The height of the pole according to the angle and distance is approximately $38.11$ meters.**