1. The problem states that Pushkar observes the top of a pole $23^3$ m high with an angle of elevation of $30^\circ$, and the distance between Pushkar and the pole is 66 m. 2. First, calculate the height of the pole. Since $23^3 = 23 \times 23 \times 23 = 12167$ m, the pole is 12167 m tall. 3. Using trigonometric relations, consider the right triangle formed by the pole, the ground distance (66 m), and the line of sight from Pushkar to the pole's top. 4. The angle of elevation $\theta = 30^\circ$, distance $d = 66$ m, height $h = 12167$ m. 5. Verify the relationship using $\tan \theta = \frac{h}{d} \implies \tan 30^\circ = \frac{12167}{66}$. 6. Calculate $\tan 30^\circ = \frac{1}{\sqrt{3}} \approx 0.577$. 7. Calculate $\frac{12167}{66} \approx 184.35$, which does not equal $\tan 30^\circ$; hence the data is inconsistent if interpreted literally. 8. However, since the task is to draw a figure, represent: - A vertical pole of height $12167$ m. - Horizontal distance of $66$ m from Pushkar to the base of the pole. - Angle of elevation $30^\circ$ from Pushkar’s eye level to the top of the pole. This figure shows a right triangle with adjacent side $66$ m, opposite side $12167$ m, and angle $30^\circ$ between the line of sight and the horizontal ground. Final answer: A right triangle with the given measurements representing Pushkar's situation.