📐 geometry
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Angle Bisector 24Bd05
1. The problem is about proving that all angles formed by bisectors of angles are equal.
2. When an angle is bisected, it is divided into two equal parts. This means each formed an
Parallelogram Right Angle 73Baa7
1. **State the problem:** Prove that a parallelogram whose diagonals are congruent has a right angle.
2. **Given:** In parallelogram $ABCD$, $\overline{AB} \parallel \overline{CD}$
Triangle Angles B816Aa
1. **Problem Statement:** Find the measures of the angles of the triangle with vertices A(-1,0), B(2,1), and C(1,-2).
2. **Formula and Rules:** To find the angles of a triangle giv
Triangle Explanation D807Fa
1. The problem is to understand and explain the properties of a triangle.
2. A triangle is a polygon with three edges and three vertices.
Hinh Chu Nhat A3A996
1. Bài toán yêu cầu chứng minh các tính chất hình học trong hình chữ nhật ABCD với các điểm H, M, N, I được xác định như sau:
2. Ta có hình chữ nhật ABCD, AH vuông góc với BD tại H
Ti So Sq Sa 7Ca96B
1. Bài toán yêu cầu tìm tỉ số $\frac{SQ}{SA}$ trong hình chóp $SABCD$ với đáy là hình bình hành tâm $O$. Các điểm $M, N, P$ lần lượt là trung điểm của các đoạn $BC, CD, SD$. Điểm $
Median Angle Bisector 182F13
1. **Problem statement:** Given triangle ABC with AM as the median. Ray MD bisects angle AMB, ray ME bisects angle AMC, and I is the intersection of DE and AM.
2. **To prove:**
Tinh Ti So 06531A
1. Bài toán: Cho hình chóp SABCD có đáy là hình bình hành tâm O. Trên cạnh SA lấy điểm M sao cho MA=2MS. Một phép chiếu song song theo phương MO lên mp(ABCD) biến điểm S thành điểm
Tỉ Số An Ac 0D4Ec6
1. Bài toán: Cho hình chóp $SABCD$ có đáy là hình bình hành tâm $O$. Trên cạnh $SA$ lấy điểm $M$ sao cho $MA=2MS$. Một phép chiếu song song theo phương $MO$ lên mặt phẳng $(ABCD)$
Triangle Por 947Ef1
1. **Problem statement:** Construct triangle POR with $PQ=8cm$, $\angle QPR=45^\circ$, and $PR=6cm$.
2. **Step 1: Draw base PQ.** Draw a line segment $PQ=8cm$.
Chord Identification 9C21E9
1. The problem asks to identify the chord in the given circle diagram.
2. A chord in a circle is a line segment with both endpoints on the circle's circumference.
Circle Sector E09B83
1. The problem asks to identify the shaded part of a circle formed by two points A and B on the circumference and the center O, with the angle at O marked as $\alpha$.
2. The shade
Angle Theta 727Ec0
1. **Stating the problem:** We are given a circle with center O and points A, B, C, D, E on the circumference. We know three arc angles near point E: 12°, 14°, and 73°, and we need
Triangle Congruence 7E95Cb
1. Problem: Determine if the given pairs of triangles are congruent and by which theorem.
2. Recall the congruence theorems:
Naming Congruent Triangles B0543E
1. The problem is to understand how to name congruent triangles.
2. Congruent triangles are triangles that have exactly the same size and shape.
Triangle Congruence F2C7D0
1. The problem asks to identify the congruence criteria for the given triangles in part (a).
2. In part (a), triangles ABC and EFD are shown with two pairs of sides marked congruen
Cone Volume A7680C
1. **Problem statement:**
A right triangle with hypotenuse $\sqrt{3}$ meters is revolved about one of its legs to form a right circular cone. We need to find the radius $r$, height
Isosceles Area Edd796
1. **Problem:** Find the area of an isosceles triangle with two equal sides of length 5 cm each and the unequal side of length 8 cm.
2. **Formula:** The area of a triangle can be f
Lateral Surface Area C67Dfd
1. **State the problem:** We need to find the lateral surface area of a square pyramid with base side length $3.11$ m and height $7.22$ m.
2. **Formula for lateral surface area of
Cone Surface Area 6F1084
1. **State the problem:** Find the total surface area of a cone with radius $r=3.78$ m and height $h=2.15$ m.
2. **Formula:** The total surface area $A$ of a cone is given by:
Points Lines Angles 337852
1. **Problem Statement:** Understand and practice concepts on Points, Lines & Planes, Angles, Angles formed by two parallel lines, Introduction to Geometrical Construction, Perpend