🧮 algebra

1. We are given the condition $x \geq y$ and want to analyze which of the options correctly completes the statement $x - z \geq$ something. 2. Since $x \geq y$, subtracting $z$ fro

1. We are given the variable \( \text{old mode} = 2.1 \).\n\n2. Since this is a statement of a value and not an equation or problem to solve, the value of \( \text{old mode} \) is

1. State the problem: Solve the inequality $-5x \geq 9$ and find the solution set from the replacement set $\{-4, -3, -2, -1, 0, 1\}$.\n\n2. Solve the inequality algebraically: \n$

1. Let's identify what the symbol \( \neq \) means in mathematics. 2. The symbol \( \neq \) stands for "not equal to." This means two values are different.

1. State the problem: Solve the equation $2x - 4 = 16$ for $x$. 2. Add 4 to both sides to isolate the term with $x$:

1. **Problem:** Create a simple algebra worksheet for students involving solving linear equations. 2. Solve for $x$: $$2x + 5 = 13$$

1. **State the problem:** Solve the equation $20 - x = 10$ for $x$. 2. **Isolate the variable:** To find $x$, subtract 20 from both sides:

1. Stating the problem: Factorise the expression $$-42b^{5}rt^{4} + 28b^{3}r^{2}t^{2}$$. 2. Identify the greatest common factor (GCF) of the coefficients: The GCF of 42 and 28 is 1

1. State the problem. Simplify the expression $2x2x$.

1. Problem statement: Simplify the expression $2x$. 2. Interpretation: The expression $2x$ denotes the product of the constant 2 and the variable $x$.

1. Problems states: Find the value of $x$ such that $$\frac{x^2 - 5x + 6}{x - 3} = 0.$$\n\n2. A fraction equals zero when its numerator equals zero and denominator is not zero. So,

1. **Problem Statement:** Given the curve points A(0,2), B(1,0), C(4,4), D(6,0) for $y=f(x)$, find new points after transformations and explain effect on $y$. For the second part,

1. State the problem: We want to find the product of the expressions $(-8x + 7)$ and $(6x - 5)$. 2. Use the distributive property (FOIL method) to multiply:

1. **State the problem:** Solve the equation $-8x = 12$ for $x$. 2. **Isolate $x$:** To find $x$, divide both sides of the equation by $-8$ to get rid of the coefficient multiplyin

1. Problem: Find which equation is equivalent to $y - 34 = x(x - 12)$.\nStep 1: Expand the right side: $$y - 34 = x^2 - 12x$$\nStep 2: Add 34 to both sides: $$y = x^2 - 12x + 34$$\

1. **Problem 38:** Find which equation is equivalent to $y - 34 = x(x - 12)$. Start by expanding the right side:

1. **Problem 38:** Find which equation is equivalent to $y - 34 = x(x - 12)$.\nExpand the right side: $$y - 34 = x^2 - 12x \Rightarrow y = x^2 - 12x + 34.$$\nNow test each option:\

1. **State the problem:** Solve the system of linear equations: $$2x + 3y = 2$$

1. The problem gives two equations: $$5y - 15 = 2x$$

1. Enuncie o problema: Simplifique a expressão $$\frac{1}{a-3} + \frac{a+1}{a+3} - \frac{1 - a}{9 - a^2}$$. 2. Observe que $$9 - a^2$$ pode ser fatorado como $$ (3 - a)(3 + a) $$.

1. **State the problem:** A person buys 5 kg of meat at a price of 500 per gram with a tax of 6% per kg. We need to find the total price for 5 kg including tax. 2. **Convert kg to