Vector Midpoint Cc0C30
1. **State the problem:** We have triangle ABC with M as the midpoint of AC. Given vectors \(\overrightarrow{AB} = 8\mathbf{a} - 4\mathbf{b}\) and \(\overrightarrow{BC} = 10\mathbf{b}\), find \(\overrightarrow{AM}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\), fully simplified.
2. **Recall vector addition rules:**
\(\overrightarrow{AC} = \overrightarrow{AB} + \overrightarrow{BC}\).
3. **Calculate \(\overrightarrow{AC}\):**
$$\overrightarrow{AC} = (8\mathbf{a} - 4\mathbf{b}) + 10\mathbf{b} = 8\mathbf{a} + 6\mathbf{b}$$
4. **Since M is midpoint of AC,**
$$\overrightarrow{AM} = \frac{1}{2} \overrightarrow{AC} = \frac{1}{2} (8\mathbf{a} + 6\mathbf{b})$$
5. **Simplify:**
$$\overrightarrow{AM} = 4\mathbf{a} + 3\mathbf{b}$$
**Final answer:**
$$\overrightarrow{AM} = 4\mathbf{a} + 3\mathbf{b}$$