1. The problem states that the factory produced $0.07 \text{ m}^3$ of grapefruit juice and $4000 \text{ cm}^3$ was removed for quality testing. We need to find out how much is left in $\text{cm}^3$.\n\n2. First, convert the total volume from cubic meters to cubic centimeters. Since $1 \text{ m} = 100 \text{ cm}$, then\n$$1 \text{ m}^3 = (100 \text{ cm})^3 = 100^3 \text{ cm}^3 = 1,000,000 \text{ cm}^3.$$\n\n3. Therefore,\n$$0.07 \text{ m}^3 = 0.07 \times 1,000,000 \text{ cm}^3 = 70,000 \text{ cm}^3.$$\n\n4. Next, subtract the volume removed for testing from the total volume:\n$$70,000 \text{ cm}^3 - 4000 \text{ cm}^3 = 66,000 \text{ cm}^3.$$\n\n5. So, the amount of grapefruit juice left is $66,000 \text{ cm}^3$.