1. **State the problem:** We need to find the distance from the UFO to satellite KA-12 given the triangle with vertices UFO, KA-12, and SAL-1. 2. **Given information:** - Distance between KA-12 and SAL-1, side $KS = 900$ km - Angle at KA-12, $\angle K = 60^\circ$ - Angle at SAL-1, $\angle S = 75^\circ$ - Distance from UFO to KA-12, side $KU = ?$ 3. **Find remaining angle:** $$ \angle U = 180^\circ - 60^\circ - 75^\circ = 45^\circ $$ 4. **Use Law of Sines:** $$ \frac{KU}{\sin 75^\circ} = \frac{KS}{\sin 45^\circ} $$ Rearranged to find $KU$: $$ KU = \frac{KS \times \sin 75^\circ}{\sin 45^\circ} $$ 5. **Calculate:** Substitute values $$ KU = \frac{900 \times \sin 75^\circ}{\sin 45^\circ} $$ Calculate sine values: $$ \sin 75^\circ = 0.9659258263, \quad \sin 45^\circ = 0.7071067812 $$ So: $$ KU = \frac{900 \times 0.9659258263}{0.7071067812} = 900 \times 1.365 $$ $$ KU = 1228.5 \text{ km} $$ 6. **Round to nearest ten kilometers:** $$ KU \approx 1230 \text{ km} $$ **Final answer:** The UFO is approximately 1230 kilometers from KA-12.