Trig Expression 622E9B
1. **State the problem:** Simplify the expression $$\cos^2 m (\tan m - 1)(\tan m + 1) - 2 \tan^2 m + \sec^2 m$$.
2. **Recall formulas and identities:**
- $$\tan^2 m + 1 = \sec^2 m$$
- $$\cos^2 m = \frac{1}{\sec^2 m}$$
- Difference of squares: $$(a - b)(a + b) = a^2 - b^2$$
3. **Simplify the product:**
$$(\tan m - 1)(\tan m + 1) = \tan^2 m - 1$$
4. **Substitute back:**
$$\cos^2 m (\tan^2 m - 1) - 2 \tan^2 m + \sec^2 m$$
5. **Rewrite using identities:**
Since $$\cos^2 m = \frac{1}{\sec^2 m}$$, the expression becomes
$$\frac{\tan^2 m - 1}{\sec^2 m} - 2 \tan^2 m + \sec^2 m$$
6. **Express $$\tan^2 m$$ in terms of $$\sec^2 m$$:**
From $$\tan^2 m + 1 = \sec^2 m$$, we get $$\tan^2 m = \sec^2 m - 1$$.
7. **Substitute $$\tan^2 m$$:**
$$\frac{(\sec^2 m - 1) - 1}{\sec^2 m} - 2(\sec^2 m - 1) + \sec^2 m = \frac{\sec^2 m - 2}{\sec^2 m} - 2 \sec^2 m + 2 + \sec^2 m$$
8. **Simplify each term:**
$$\frac{\sec^2 m}{\sec^2 m} - \frac{2}{\sec^2 m} - 2 \sec^2 m + 2 + \sec^2 m = 1 - \frac{2}{\sec^2 m} - 2 \sec^2 m + 2 + \sec^2 m$$
9. **Combine like terms:**
$$1 + 2 + \sec^2 m - 2 \sec^2 m - \frac{2}{\sec^2 m} = 3 - \sec^2 m - \frac{2}{\sec^2 m}$$
10. **Rewrite $$\frac{2}{\sec^2 m}$$ as $$2 \cos^2 m$$:**
$$3 - \sec^2 m - 2 \cos^2 m$$
11. **Final simplified expression:**
$$\boxed{3 - \sec^2 m - 2 \cos^2 m}$$