1. **Problem:** Find $x$ in triangle (a) with angles 85°, 45°, and side 9cm opposite 85°. 2. **Step 1:** Use the fact that the sum of angles in a triangle is 180°. $$x = 180° - 85° - 45° = 50°$$ 3. **Step 2:** Use the Law of Sines to find the side opposite $x$ (which is 50°): $$\frac{a}{\sin A} = \frac{b}{\sin B}$$ Here, $a = 9$ cm opposite 85°, $b = x$ opposite 50°. 4. **Step 3:** Substitute known values: $$\frac{9}{\sin 85°} = \frac{x}{\sin 50°}$$ 5. **Step 4:** Solve for $x$: $$x = \frac{9 \times \sin 50°}{\sin 85°}$$ Calculate: $$\sin 50° \approx 0.7660, \quad \sin 85° \approx 0.9962$$ $$x \approx \frac{9 \times 0.7660}{0.9962} \approx 6.92 \text{ cm}$$ **Final answer:** $x \approx 6.92$ cm --- **Note:** There are multiple questions, but per instructions, only the first problem is solved here.