Subjects trigonometry

Tree Height 6A09Ca

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Tree Height 6A09Ca


1. **State the problem:** From a point on the ground 15 meters from the base of a tree, the angle of elevation to the top of the tree is 35°. We need to find the height of the tree. 2. **Formula and explanation:** We use the tangent function in a right triangle, which relates the angle to the opposite side (height of the tree, $h$) and adjacent side (distance from the tree, 15 m): $$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{h}{15}$$ 3. **Calculate the height:** Rearranging the formula to solve for $h$: $$h = 15 \times \tan(35^\circ)$$ Using a calculator or trigonometric tables: $$\tan(35^\circ) \approx 0.7002$$ So, $$h = 15 \times 0.7002 = 10.503$$ 4. **Interpretation:** The height of the tree is approximately 10.5 meters. **Final answer:** $$\boxed{10.5 \text{ meters}}$$