Tree Height 6A09Ca
1. **State the problem:**
From a point on the ground 15 meters from the base of a tree, the angle of elevation to the top of the tree is 35°. We need to find the height of the tree.
2. **Formula and explanation:**
We use the tangent function in a right triangle, which relates the angle to the opposite side (height of the tree, $h$) and adjacent side (distance from the tree, 15 m):
$$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{h}{15}$$
3. **Calculate the height:**
Rearranging the formula to solve for $h$:
$$h = 15 \times \tan(35^\circ)$$
Using a calculator or trigonometric tables:
$$\tan(35^\circ) \approx 0.7002$$
So,
$$h = 15 \times 0.7002 = 10.503$$
4. **Interpretation:**
The height of the tree is approximately 10.5 meters.
**Final answer:**
$$\boxed{10.5 \text{ meters}}$$