Sinusoidal Equation 1Bda61
1. **State the problem:** We need to find the equation of a sinusoidal function based on the given graph description.
2. **Identify key features from the graph:**
- The sinusoid starts near $y=1$ at $x=-\frac{\pi}{24}$.
- It reaches a minimum near $y=-4$ between $x=\frac{\pi}{24}$ and $x=\frac{\pi}{12}$.
- It then rises to above $y=5$ slightly before $x=\frac{\pi}{8}$.
3. **Determine amplitude ($A$):**
- The maximum value is about $5$ and the minimum is about $-4$.
- Amplitude $A = \frac{\text{max} - \text{min}}{2} = \frac{5 - (-4)}{2} = \frac{9}{2} = 4.5$.
4. **Determine vertical shift ($D$):**
- Vertical shift $D = \frac{\text{max} + \text{min}}{2} = \frac{5 + (-4)}{2} = \frac{1}{2} = 0.5$.
5. **Determine period ($T$):**
- The sinusoid goes from near a midline point at $x=-\frac{\pi}{24}$, to a minimum between $\frac{\pi}{24}$ and $\frac{\pi}{12}$, and back to a maximum near $\frac{\pi}{8}$.
- The distance between minimum and maximum is roughly $\frac{\pi}{8} - \frac{\pi}{12} = \frac{3\pi}{24} - \frac{2\pi}{24} = \frac{\pi}{24}$.
- Since half a period corresponds to the distance between minimum and maximum, half period $= \frac{\pi}{24}$.
- Therefore, full period $T = 2 \times \frac{\pi}{24} = \frac{\pi}{12}$.
6. **Calculate angular frequency ($\omega$):**
- $\omega = \frac{2\pi}{T} = \frac{2\pi}{\frac{\pi}{12}} = 24$.
7. **Determine phase shift ($\phi$):**
- The sinusoid starts near the midline at $x=-\frac{\pi}{24}$ and is decreasing, which matches the behavior of a cosine shifted to the right.
- Using the cosine form: $y = A \cos(\omega x + \phi) + D$.
- At $x = -\frac{\pi}{24}$, $y \approx 1$.
- Substitute known values:
$$1 = 4.5 \cos\left(24 \times \left(-\frac{\pi}{24}\right) + \phi\right) + 0.5$$
$$1 = 4.5 \cos(-\pi + \phi) + 0.5$$
$$1 - 0.5 = 4.5 \cos(-\pi + \phi)$$
$$0.5 = 4.5 \cos(-\pi + \phi)$$
$$\cos(-\pi + \phi) = \frac{0.5}{4.5} = \frac{1}{9}$$
- Since $\cos(-\pi + \phi) = -\cos(\phi)$, we have:
$$-\cos(\phi) = \frac{1}{9} \implies \cos(\phi) = -\frac{1}{9}$$
- So $\phi = \arccos\left(-\frac{1}{9}\right)$.
8. **Final equation:**
$$
y = 4.5 \cos\left(24x + \arccos\left(-\frac{1}{9}\right)\right) + 0.5
$$
This equation models the sinusoidal function described by the graph.