Subjects trigonometry

Sin Shift Zeros 4A0C6F

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Sin Shift Zeros 4A0C6F


1. We are asked to find the zeros (nulpunt) of the function $y = \sin\left(x - \frac{\pi}{4}\right)$. 2. The zeros of the sine function occur where the argument is an integer multiple of $\pi$, i.e., where $\sin(\theta) = 0$ if and only if $\theta = k\pi$ for any integer $k$. 3. Set the inside of the sine function equal to $k\pi$: $$x - \frac{\pi}{4} = k\pi$$ 4. Solve for $x$: $$x = k\pi + \frac{\pi}{4}$$ 5. This means the zeros of $y = \sin\left(x - \frac{\pi}{4}\right)$ occur at $$x = \frac{\pi}{4} + k\pi, \quad k \in \mathbb{Z}$$ 6. In plain language, the function crosses the x-axis at $x = \frac{\pi}{4}$ plus any integer multiple of $\pi$. This is because shifting the sine function by $\frac{\pi}{4}$ shifts its zeros accordingly.