Sin Shift Zeros 4A0C6F
1. We are asked to find the zeros (nulpunt) of the function $y = \sin\left(x - \frac{\pi}{4}\right)$.
2. The zeros of the sine function occur where the argument is an integer multiple of $\pi$, i.e., where $\sin(\theta) = 0$ if and only if $\theta = k\pi$ for any integer $k$.
3. Set the inside of the sine function equal to $k\pi$:
$$x - \frac{\pi}{4} = k\pi$$
4. Solve for $x$:
$$x = k\pi + \frac{\pi}{4}$$
5. This means the zeros of $y = \sin\left(x - \frac{\pi}{4}\right)$ occur at
$$x = \frac{\pi}{4} + k\pi, \quad k \in \mathbb{Z}$$
6. In plain language, the function crosses the x-axis at $x = \frac{\pi}{4}$ plus any integer multiple of $\pi$. This is because shifting the sine function by $\frac{\pi}{4}$ shifts its zeros accordingly.