1. The problem is to find the exact value of $\sin(\frac{\pi}{6})$. 2. The formula for sine of special angles is based on the unit circle and known values: $\sin(\frac{\pi}{6}) = \frac{1}{2}$. 3. Important rule: $\sin(\theta)$ for $\theta = \frac{\pi}{6}$ (30 degrees) is exactly $\frac{1}{2}$. 4. Therefore, the exact value of $\sin(\frac{\pi}{6})$ is: $$\sin\left(\frac{\pi}{6}\right) = \frac{1}{2}$$ This is a fundamental trigonometric value often memorized for solving problems involving angles of 30 degrees.