Subjects trigonometry

Secant Values

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Secant Values


1. **State the problem:** We need to fill in the missing values in the table for the function $y = -\sec(x)$ at $x = 0.1$ and $x = 0.2$ to 3 decimal places. 2. **Recall the function:** $y = -\sec(x) = -\frac{1}{\cos(x)}$. 3. **Calculate Box 1 ($x=0.1$):** $$\cos(0.1) \approx 0.995$$ $$y = -\frac{1}{0.995} \approx -1.005$$ Rounded to 3 decimals: $-1.005$. 4. **Calculate Box 2 ($x=0.2$):** $$\cos(0.2) \approx 0.980$$ $$y = -\frac{1}{0.980} \approx -1.020$$ Rounded to 3 decimals: $-1.020$. 5. **Summary:** - Box 1 = $-1.005$ - Box 2 = $-1.020$ These values fit the pattern of the curve $y = -\sec(x)$ between $x=0$ and $x=0.5$.