Sec Tan 30 0Ff66F
1. **Problem Statement:** Given \(\cos 30^\circ = \frac{\sqrt{3}}{2}\) and \(\cot 30^\circ = \sqrt{3}\), find \(\sec 30^\circ\) and \(\tan 30^\circ\).
2. **Recall the definitions:**
- \(\sec \theta = \frac{1}{\cos \theta}\)
- \(\tan \theta = \frac{1}{\cot \theta}\)
3. **Calculate \(\sec 30^\circ\):**
\[
\sec 30^\circ = \frac{1}{\cos 30^\circ} = \frac{1}{\frac{\sqrt{3}}{2}} = \frac{2}{\sqrt{3}} = \frac{2\sqrt{3}}{3}
\]
4. **Calculate \(\tan 30^\circ\):**
\[
\tan 30^\circ = \frac{1}{\cot 30^\circ} = \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3}
\]
5. **Interpretation:**
- \(\sec 30^\circ = \frac{2\sqrt{3}}{3}\) matches option 3.
- \(\tan 30^\circ = \frac{\sqrt{3}}{3}\) is also found.
**Final answers:**
- \(\sec 30^\circ = \frac{2\sqrt{3}}{3}\)
- \(\tan 30^\circ = \frac{\sqrt{3}}{3}\)