Right Angle X
1. **State the problem:** We need to find the size of angle $x$ in a right-angled triangle where the right angle is at the bottom left corner.
2. **Identify sides relevant to angle $x$:**
- Opposite side to angle $x$ is the vertical side of length 5.8 m.
- Hypotenuse is the diagonal side of length 9.6 m.
3. **Choose the trigonometric ratio:**
Since we know the opposite side and hypotenuse, we use sine:
$$\sin x = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{5.8}{9.6}$$
4. **Calculate sine value:**
$$\sin x = 0.6042$$
5. **Find angle $x$ by inverse sine:**
$$x = \sin^{-1}(0.6042)$$
6. **Calculate angle $x$ using a calculator:**
$$x \approx 37.1^{\circ}$$
7. **Round to 1 decimal place:**
$$x = 37.1^{\circ}$$
**Final answer:** Angle $x$ is approximately $37.1^\circ$ to 1 decimal place.