1. The problem is to find the range of the function $y = 3\sin(\theta)$.\n\n2. Recall that the sine function $\sin(\theta)$ has a range of $[-1, 1]$. This means $\sin(\theta)$ can take any value from $-1$ up to $1$.\n\n3. The function $y = 3\sin(\theta)$ is a vertical stretch of the sine function by a factor of 3. To find the new range, multiply the original range by 3.\n\n4. Multiply the minimum and maximum values of $\sin(\theta)$ by 3:\n$$\text{Minimum: } 3 \times (-1) = -3$$\n$$\text{Maximum: } 3 \times 1 = 3$$\n\n5. Therefore, the range of $y = 3\sin(\theta)$ is $[-3, 3]$.\n\nIn simple terms, the output values of $y$ will always be between $-3$ and $3$ inclusive.