London Eye Height
1. **Problem Statement:** We need to find which equation correctly models the height $H(t)$ of a rider on the London Eye as a function of time $t$ in minutes.
2. **Given Information:**
- Radius of the wheel $r = 68$ m.
- One complete revolution takes 30 minutes.
- Starting height at $t=0$ is 2 m.
- The height function is of the form $$H(t) = a \sin|b(t - c)| + d$$
3. **Understanding the parameters:**
- Amplitude $a$ corresponds to the radius of the wheel or half the vertical distance covered.
- Vertical shift $d$ corresponds to the center height of the wheel above the ground.
- The period $T$ of the sine function is related to $b$ by $$T = \frac{2\pi}{b}$$
- Horizontal shift $c$ adjusts the phase to match the starting height.
4. **Calculate the period and $b$:**
- The wheel completes one revolution in 30 minutes, so the period $T = 30$.
- Using $$b = \frac{2\pi}{T} = \frac{2\pi}{30} = \frac{\pi}{15}$$
5. **Determine amplitude $a$ and vertical shift $d$:**
- The wheel radius is 68 m, so the amplitude $a$ should be 68.
- The lowest point is 2 m, so the center height $d$ is radius + lowest point = $68 + 2 = 70$ m.
6. **Check the horizontal shift $c$:**
- The function starts at height 2 m at $t=0$, which is the minimum point.
- For a sine function, minimum occurs at phase $\frac{3\pi}{2}$ or by shifting the function by $7.5$ minutes.
- So, $c = 7.5$.
7. **Evaluate the options:**
- Option A: $a=68$, $b=\frac{\pi}{15}$, $c=-7.5$, $d=68$ (vertical shift too low)
- Option B: $a=68$, $b=\frac{\pi}{15}$, $c=7.5$, $d=70$ (matches amplitude, period, shift, and vertical shift)
- Option C: $a=34$, $b=\frac{\pi}{30}$, $c=-7.5$, $d=70$ (amplitude and period incorrect)
- Option D: $a=34$, $b=\frac{\pi}{30}$, $c=7.5$, $d=68$ (amplitude and vertical shift incorrect)
8. **Conclusion:** The correct equation is Option B:
$$H(t) = 68 \sin\left|\frac{\pi}{15}(t - 7.5)\right| + 70$$
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**Additional question:**
Given $f(\theta) = \cos(n\theta)$ has the same period as $g(\theta) = \tan \theta$, find $n$.
- Period of $\tan \theta$ is $\pi$.
- Period of $\cos(n\theta)$ is $$\frac{2\pi}{n}$$
- Set equal: $$\frac{2\pi}{n} = \pi \Rightarrow n = 2$$
**Final answers:**
- Height function: $$H(t) = 68 \sin\left|\frac{\pi}{15}(t - 7.5)\right| + 70$$
- Value of $n$ for cosine function: $2$