1. The problem is to find side AC in triangle ABC using the Law of Sines. 2. The Law of Sines formula is $$\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}$$ where $a,b,c$ are sides opposite angles $A,B,C$ respectively. 3. Given angle $A=92^\circ$, angle $B=28^\circ$, and side $BC=15$ yd (opposite angle $A$), we want to find side $AC=b$ opposite angle $B$. 4. Using the Law of Sines: $$\frac{b}{\sin 28^\circ} = \frac{15}{\sin 92^\circ}$$ 5. Rearranged to solve for $b$: $$b = \frac{\sin 28^\circ \times 15}{\sin 92^\circ}$$ 6. To calculate this on a calculator: - Enter $\sin 28^\circ$ (make sure calculator is in degree mode). - Multiply by 15. - Divide by $\sin 92^\circ$. 7. Evaluating: $$b = \frac{0.4695 \times 15}{0.9994} \approx \frac{7.0425}{0.9994} \approx 7.0$$ 8. So, side $AC$ is approximately 7.0 yards. This method applies the Law of Sines and shows how to input the expression into a calculator step-by-step.