1. **State the problem:** We are given a triangle with angles 25° and 96°, and the side opposite the 25° angle is 13 units. We need to find the length of the side opposite the 96° angle using the law of sines. 2. **Find the third angle:** The sum of angles in a triangle is 180°. $$ 180^\circ - 96^\circ - 25^\circ = 59^\circ $$ 3. **Set up the law of sines:** $$ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} $$ Here, let $a = 13$ be opposite $25^\circ$, and $b$ be the side opposite $96^\circ$ (the side we want to find). 4. **Apply the law of sines:** $$ \frac{13}{\sin 25^\circ} = \frac{b}{\sin 96^\circ} $$ 5. **Solve for $b$:** $$ b = \frac{13 \times \sin 96^\circ}{\sin 25^\circ} $$ 6. **Calculate the sines:** $$ \sin 25^\circ \approx 0.4226 $$ $$ \sin 96^\circ \approx 0.9945 $$ 7. **Compute $b$:** $$ b = \frac{13 \times 0.9945}{0.4226} \approx \frac{12.9285}{0.4226} \approx 30.59 $$ **Final answer:** The length of the side opposite the 96° angle is approximately **30.59** units.