1. **Problem Statement:** A kite is flying at a height of 75 m from the ground, attached to a string inclined at 60° to the horizontal. Find the length of the string to the nearest meter. 2. **Formula and Explanation:** We use the trigonometric relation in a right triangle: $$\sin \theta = \frac{\text{opposite}}{\text{hypotenuse}}$$ where the opposite side is the height of the kite (75 m), the hypotenuse is the length of the string (let it be $L$), and $\theta = 60^\circ$ is the angle of inclination. 3. **Calculation:** $$\sin 60^\circ = \frac{75}{L}$$ We know $\sin 60^\circ = \frac{\sqrt{3}}{2} \approx 0.866$. So, $$0.866 = \frac{75}{L} \implies L = \frac{75}{0.866}$$ 4. **Simplify:** $$L \approx 86.6$$ 5. **Final answer:** The length of the string is approximately **87 meters**.