Subjects trigonometry

Kite Height 7953Ff

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Kite Height 7953Ff


1. **Problem statement:** We need to find the height of the kite above the ground given the angle of elevation, the length of the string, and the sag in the string. 2. **Given:** - Angle of elevation, $\theta = 30^\circ$ - Length of the string, $L = 250$ m - Sag in the string, $s = 5$ m 3. **Understanding the problem:** The string is not taut; it sags by 5 m. The effective length of the string that contributes to the height is the length minus the sag: $L_{effective} = L - s = 250 - 5 = 245$ m. 4. **Formula used:** The height $h$ of the kite can be found using the sine of the angle of elevation: $$h = L_{effective} \times \sin(\theta)$$ 5. **Calculation:** $$h = 245 \times \sin(30^\circ)$$ Since $\sin(30^\circ) = 0.5$, $$h = 245 \times 0.5 = 122.5$$ 6. **Answer:** The height of the kite is $122.5$ meters.