1. **Problem statement:** Convert 30° into radians and find the arc length $l$ when radius $r=6$ cm. 2. **Conversion formula:** Radians $= \frac{\pi}{180} \times$ degrees. 3. Substituting 30°: $$30 \times \frac{\pi}{180} = \frac{30\pi}{180} = \frac{\pi}{6} \approx 0.524$$ radians. 4. **Calculate arc length $l$: $$l = r \times \theta = 6 \times 0.524 = 3.144$$ cm (using $\pi = 3.14$). 5. **Additional info:** Given $r=15$ cm and $\theta=60^\circ$ convert $60^\circ$ to radians: $$60 \times \frac{\pi}{180} = \frac{\pi}{3} \approx 1.047$$ radians. 6. The arc length for this is $$l = 15 \times 1.047 = 15.705$$ cm. **Final answers:** - $30^\circ$ is approximately $0.524$ radians. - Arc length for $r=6$ cm, $30^\circ$ is $3.144$ cm. - $60^\circ$ is approximately $1.047$ radians. - Arc length for $r=15$ cm, $60^\circ$ is $15.705$ cm.