1. **Problem:** A construction worker looks up at the top of a crane 60 meters tall. The angle of elevation to the top is 35 degrees. Find the distance from the worker to the base of the crane. 2. **Formula and rules:** We use the tangent function in a right triangle: $$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$ where $\theta$ is the angle of elevation, opposite side is the height of the crane, and adjacent side is the distance from the worker to the base. 3. **Work:** Let $d$ be the distance from the worker to the base. $$\tan(35^\circ) = \frac{60}{d} \implies d = \frac{60}{\tan(35^\circ)}$$ Calculate $\tan(35^\circ)$: $$\tan(35^\circ) \approx 0.7002$$ So, $$d = \frac{60}{0.7002} \approx 85.7$$ meters. 4. **Answer:** The worker is approximately 85.7 meters from the base of the crane.