Cosine Power Four A638Ec
1. **Stating the problem:**
We are given the complex number with argument $\text{Arg } Z = -\pi$ and real part $\text{Re } Z = -1$, and we want to evaluate $\cos^4 x$ for some $x$.
2. **Understanding the complex number:**
The argument $\text{Arg } Z = -\pi$ means the angle of the complex number $Z$ in the complex plane is $-\pi$ radians, which points directly to the negative real axis.
3. **Using the real part:**
Since $\text{Re } Z = -1$ and the argument is $-\pi$, the complex number is $Z = -1 + 0i$.
4. **About $\cos^4 x$:**
The expression $\cos^4 x$ means $(\cos x)^4$, the cosine of $x$ raised to the fourth power.
5. **No specific $x$ given:**
Since $x$ is not specified, we cannot compute a numeric value for $\cos^4 x$. However, we can express $\cos^4 x$ in terms of multiple angles using the power-reduction formula.
6. **Power-reduction formula:**
Recall that
$$\cos^2 x = \frac{1 + \cos 2x}{2}$$
Therefore,
$$\cos^4 x = (\cos^2 x)^2 = \left(\frac{1 + \cos 2x}{2}\right)^2 = \frac{1}{4}(1 + 2\cos 2x + \cos^2 2x)$$
7. **Reduce $\cos^2 2x$ further:**
Using the formula again,
$$\cos^2 2x = \frac{1 + \cos 4x}{2}$$
8. **Substitute back:**
$$\cos^4 x = \frac{1}{4}\left(1 + 2\cos 2x + \frac{1 + \cos 4x}{2}\right) = \frac{1}{4}\left(1 + 2\cos 2x + \frac{1}{2} + \frac{\cos 4x}{2}\right)$$
9. **Simplify:**
$$\cos^4 x = \frac{1}{4}\left(\frac{3}{2} + 2\cos 2x + \frac{\cos 4x}{2}\right) = \frac{3}{8} + \frac{1}{2}\cos 2x + \frac{1}{8}\cos 4x$$
**Final expression:**
$$\boxed{\cos^4 x = \frac{3}{8} + \frac{1}{2}\cos 2x + \frac{1}{8}\cos 4x}$$
This formula expresses $\cos^4 x$ in terms of cosines of multiple angles, which is useful for integration or simplification.
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**Summary:**
- The complex number $Z$ is $-1$ on the real axis.
- The expression $\cos^4 x$ can be rewritten using power-reduction formulas as above.