1. Let's start by understanding the problem: you want to solve a trigonometric expression by taking common factors $h_1$ and $h_2$. 2. The general approach is to factor out the common terms $h_1$ and $h_2$ from the given trigonometric expression. 3. Suppose the expression is of the form $h_1 \sin x + h_2 \cos x$, we can factor it as $h_1(\sin x) + h_2(\cos x)$. 4. To solve or simplify, we can use the trigonometric identity: $$a \sin x + b \cos x = \sqrt{a^2 + b^2} \sin(x + \alpha)$$ where $\alpha = \arctan\left(\frac{b}{a}\right)$ if $a \neq 0$. 5. Applying this, the expression becomes: $$h_1 \sin x + h_2 \cos x = \sqrt{h_1^2 + h_2^2} \sin\left(x + \arctan\left(\frac{h_2}{h_1}\right)\right)$$ 6. This form is easier to analyze or solve for $x$ depending on the problem context. 7. If you provide the exact expression, I can demonstrate the factoring and solving steps in detail.