1. **State the problem:** Find the angle $\theta$ in a right triangle where the hypotenuse is 8 m and the adjacent side to $\theta$ is 5 m. 2. **Formula used:** We use the cosine function because cosine relates the adjacent side and hypotenuse in a right triangle: $$\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}$$ 3. **Apply the values:** $$\cos(\theta) = \frac{5}{8} = 0.625$$ 4. **Find $\theta$:** Use the inverse cosine (arccos) function on a calculator: $$\theta = \cos^{-1}(0.625)$$ 5. **Calculate using a simple calculator:** - Enter 0.625 - Press the inverse cosine button (usually labeled $\cos^{-1}$ or $\arccos$) - The calculator gives $\theta \approx 51.3^\circ$ 6. **Final answer:** $$\theta = 51.3^\circ$$ (rounded to 1 decimal place)