1. **State the problem:** We need to find angle $A$ in a right triangle where side $a = 103.3$ cm, side $b = 152.5$ cm, and angle $C = 90^\circ$. 2. **Recall the ABCabc format:** In this format, $A$, $B$, and $C$ are angles opposite sides $a$, $b$, and $c$ respectively. Since $C = 90^\circ$, the triangle is right-angled at $C$. 3. **Use the tangent function:** For right triangles, $\tan(A) = \frac{\text{opposite}}{\text{adjacent}} = \frac{a}{b}$. 4. **Calculate $\tan(A)$:** $$\tan(A) = \frac{103.3}{152.5} \approx 0.6777$$ 5. **Find angle $A$ using inverse tangent:** $$A = \tan^{-1}(0.6777)$$ 6. **Evaluate $A$:** $$A \approx 34.2^\circ$$ 7. **Final answer:** Angle $A$ is approximately $34.2$ degrees to the nearest tenth.