1. **State the problem:** We have two tangents intersecting at station 4107 with given data about compound curves: angles $I_1 = 31^\circ$, $I_2 = 35^\circ$, and deflection angles $D_1 = 3^\circ$, $D_2 = 5^\circ$. We want to find the stationing at the Point of Curvature (PC). 2. **Identify key relations:** The stationing at PC is calculated from the tangent intersection point by subtracting the tangent length of the first curve. Tangent length for a curve is given by $$T = R \tan\left(\frac{I}{2}\right)$$ but since radius is not provided, we use deflection angles and the given intersection station to find PC. 3. **Calculate total interior angle $I$ of compound curve:** $$I = I_1 + I_2 = 31^\circ + 35^\circ = 66^\circ$$ 4. **Calculate sum of deflection angles:** $$D = D_1 + D_2 = 3^\circ + 5^\circ = 8^\circ$$ 5. **Calculate tangent length difference using angles:** Assuming that the deflection angle corresponds to the angle between PC and intersection, stationing at PC can be found by subtracting shift caused by deflection from STA at intersection point: $$\text{Station PC} = \text{Station Intersection} - \frac{D}{2} \times \text{some factor}$$ 6. **But with insufficient data (e.g., radius or length), assume station of PC lies at: ** $$\text{PC station} = 4107 - T_1$$ Given insufficient details, best estimate with input is subtracting the deflection angle $D_1=3^\circ$ converted to linear station. 7. **Final answer:** Since no length units or radius provided, stationing at PC is approximately: $$\boxed{4107 - 3 = 4104}$$ (Assuming 1 degree deflection equals one station unit, commonly 100 feet, but exact unit conversion is not given.) **Note:** More data (radius or curve length) is needed for exact calculation, but given data, station at PC is around 4104.