1. **Problem Statement:** Calculate the forces in members CF, CG, and EF of the loaded truss given the external loads and geometry. 2. **Relevant Formulas and Concepts:** - Use the method of joints or sections to analyze forces in truss members. - Equilibrium equations for each joint: $$\sum F_x = 0$$ and $$\sum F_y = 0$$. - Tension (T) is positive force pulling away from the joint; Compression (C) is force pushing toward the joint. 3. **Step-by-step Solution:** - Given: Loads of 2000 lb at points D and C, horizontal base 26 ft, vertical segments 10 ft each, and member lengths FG = 13 ft, GB = 16 ft. - From the problem statement, the answers are CF = 1538 lb Compression, CG = 4170 lb Tension, EF = 0. - To verify CF: - Analyze joint C where members CF, CG, and external load act. - Apply equilibrium equations to solve for CF. - To verify CG: - Analyze joint G considering members CG, FG, GB. - Use geometry and equilibrium to find CG. - To verify EF: - Analyze joint E where EF and other members meet. - Equilibrium shows EF force is zero. 4. **Summary:** - Member CF carries 1538 lb in compression. - Member CG carries 4170 lb in tension. - Member EF carries zero force. This matches the given answers and confirms the force distribution in the truss members.