1. **Stating the problem:** We have a right triangle with a distributed load of 5 kN/m acting along the hypotenuse, which has length calculated from the base 2.3 m and height 1.2 m. 2. **Calculate the length of the hypotenuse:** Using the Pythagorean theorem: $$\text{hypotenuse} = \sqrt{(2.3)^2 + (1.2)^2} = \sqrt{5.29 + 1.44} = \sqrt{6.73} \approx 2.594 \, \text{m}$$ 3. **Calculate the total distributed load:** The distributed load is 5 kN/m along the hypotenuse, so total load is: $$5 \times 2.594 = 12.97 \, \text{kN}$$ 4. **Calculate the resultant force of the distributed load:** This force acts at the midpoint of the hypotenuse. 5. **Given a 6 kN horizontal force acting to the left at the bottom-left vertex.** 6. **Supports:** Left vertex is pinned (fixed), right vertex is roller support. 7. **Summary:** - Distributed load total: 12.97 kN acting downward along hypotenuse midpoint. - Point load: 6 kN horizontal left at bottom-left vertex. - Geometry: right triangle with base 2.3 m, height 1.2 m, hypotenuse 2.594 m. This setup is typical for static analysis of forces and moments on the structure. **Final answers:** - Hypotenuse length: $2.594$ m - Total distributed load: $12.97$ kN - Location of distributed load resultant: midpoint of hypotenuse - Point load: $6$ kN horizontal left at bottom-left vertex