1. The problem asks for the area (probability) between the z-scores $-1.73$ and $0.49$ on the standard normal distribution curve. 2. The area under the standard normal curve between two z-scores corresponds to the probability that a value falls between those z-scores. 3. Use the standard normal distribution table or a calculator to find the cumulative probabilities: - $P(Z < 0.49) \approx 0.6879$ - $P(Z < -1.73) \approx 0.0418$ 4. The area between $-1.73$ and $0.49$ is the difference of these cumulative probabilities: $$P(-1.73 < Z < 0.49) = P(Z < 0.49) - P(Z < -1.73) = 0.6879 - 0.0418 = 0.6461$$ 5. Therefore, the probability (area) between the z-scores $-1.73$ and $0.49$ is approximately $0.6461$ or 64.61%.