Wax Amount
1. The problem involves interpreting a line plot showing the "Amount of melted yellow wax" at three points: 0, 1/2, and 1.
2. Each point has a number of X's stacked vertically representing frequency: 3 at 0, 3 at 1/2, and 2 at 1.
3. This data can be summarized as a frequency distribution:
- At 0: frequency = 3
- At 1/2: frequency = 3
- At 1: frequency = 2
4. To analyze this data, we can calculate the mean amount of melted wax using the formula for weighted average:
$$\text{Mean} = \frac{\sum (x_i \times f_i)}{\sum f_i}$$
where $x_i$ are the values and $f_i$ their frequencies.
5. Calculate the numerator:
$$0 \times 3 + \frac{1}{2} \times 3 + 1 \times 2 = 0 + \frac{3}{2} + 2 = \frac{3}{2} + 2 = \frac{3}{2} + \frac{4}{2} = \frac{7}{2}$$
6. Calculate the denominator (total frequency):
$$3 + 3 + 2 = 8$$
7. Compute the mean:
$$\text{Mean} = \frac{7/2}{8} = \frac{7}{2} \times \frac{1}{8} = \frac{7}{16}$$
8. Therefore, the average amount of melted yellow wax is $\frac{7}{16}$.
9. This means on average, the melted wax amount is slightly less than half the maximum value of 1.