1. **State the problem:** We need to find the upper quartile (Q3) of the number of newspaper deliveries given the data set: 40, 50, 60, 70, 80, 90. 2. **Recall the definition:** The upper quartile (Q3) is the median of the upper half of the data, which separates the highest 25% of the data from the rest. 3. **Order the data:** The data is already ordered: 40, 50, 60, 70, 80, 90. 4. **Find the median (Q2):** Since there are 6 data points (even number), the median is the average of the 3rd and 4th values: $$\text{Median} = \frac{60 + 70}{2} = \frac{130}{2} = 65$$ 5. **Split the data into halves:** - Lower half: 40, 50, 60 - Upper half: 70, 80, 90 6. **Find the upper quartile (Q3):** The median of the upper half is the middle value of 70, 80, 90, which is 80. **Final answer:** The upper quartile of the number of newspaper deliveries is **80** deliveries.