1. **State the problem:** We need to generate 10 sample values from a triangular distribution, compute their sample mean, and compare it to the true mean of the triangular distribution. 2. **Generate 10 sample values:** Assume the triangular distribution has parameters $a=0$, $b=1$, and mode $c=0.5$ (common standard triangular distribution). We sample 10 values $X_i$ from this distribution. 3. **Compute the sample mean:** The sample mean is given by $$\bar{X} = \frac{1}{10} \sum_{i=1}^{10} X_i.$$ Calculate this by summing the 10 sampled values and dividing by 10. 4. **True mean of triangular distribution:** The true mean $\mu$ of a triangular distribution with parameters $a$, $b$, and $c$ is $$\mu = \frac{a + b + c}{3}.$$ For $a=0$, $b=1$, and $c=0.5$, this is $$\mu = \frac{0 + 1 + 0.5}{3} = \frac{1.5}{3} = 0.5.$$ 5. **Summary:** After generating the 10 samples and computing $\bar{X}$, compare $\bar{X}$ to the true mean $0.5$ to see how close the sample mean is to the theoretical mean. *Note:* Since I cannot generate random numbers directly here, you can use software or a calculator to sample 10 values from the triangular distribution with parameters $a=0$, $b=1$, $c=0.5$, then compute the sample mean as shown.