1. **State the problem:** We are given that the duration of a T20 cricket match is normally distributed with mean $\mu = 195$ minutes and standard deviation $\sigma = 9$ minutes. We want to find the probability that the match will be completed within 3.5 hours. 2. **Convert hours to minutes:** Since the mean and standard deviation are in minutes, convert 3.5 hours to minutes: $$3.5 \text{ hours} = 3.5 \times 60 = 210 \text{ minutes}$$ 3. **Use the normal distribution formula:** The probability that the match duration $X$ is less than or equal to 210 minutes is: $$P(X \leq 210)$$ 4. **Standardize the variable:** Convert $X$ to the standard normal variable $Z$ using: $$Z = \frac{X - \mu}{\sigma} = \frac{210 - 195}{9} = \frac{15}{9} = 1.67$$ 5. **Find the probability from the standard normal distribution:** Using standard normal distribution tables or a calculator, $$P(Z \leq 1.67) \approx 0.9525$$ 6. **Interpretation:** There is approximately a 95.25% chance that tomorrow's T20 cricket match will be completed within 3.5 hours. **Final answer:** $$\boxed{0.9525}$$