1. **Stating the problem:** We need to compute the value of $t$ using the formula $$t = \frac{xs - \mu}{\sqrt{n}}$$ and check if $t > 1.699$. 2. **Formula explanation:** - $xs$ is the sample mean or observed value. - $\mu$ is the population mean or hypothesized value. - $n$ is the sample size. - The formula calculates the $t$-statistic, which measures how many standard errors the sample mean is from the population mean. 3. **Important rules:** - The denominator is $\sqrt{n}$, the square root of the sample size. - The numerator is the difference between the sample mean and population mean. - The $t$-value is compared to a critical value (here 1.699) to determine significance. 4. **Intermediate work:** - Substitute the known values of $xs$, $\mu$, and $n$ into the formula. - Calculate the numerator: $xs - \mu$. - Calculate the denominator: $\sqrt{n}$. - Divide numerator by denominator to get $t$. 5. **Final step:** - Compare the computed $t$ to 1.699. - If $t > 1.699$, the condition is true; otherwise, false. **Note:** Since specific values for $xs$, $\mu$, and $n$ are not provided, the exact numeric value of $t$ cannot be computed here.