1. **Problem A: Find scores based on standard deviations from the mean** Given: mean $\mu = 58.4$, standard deviation $\sigma = 7.6$. Formula: Score $= \mu + (z \times \sigma)$ where $z$ is the number of standard deviations. 1. One standard deviation above the mean: $$\text{Score} = 58.4 + (1 \times 7.6) = 58.4 + 7.6 = 66$$ 2. Three standard deviations below the mean: $$\text{Score} = 58.4 + (-3 \times 7.6) = 58.4 - 22.8 = 35.6$$ **Answer:** - One standard deviation above mean: $66$ - Three standard deviations below mean: $35.6$