1. **State the problem:** We have a split-plot design experiment with two factors: grow media (whole-plot factor) and fertilizer formulation (sub-plot factor), replicated three times (farms A, B, C). We want to analyze the yield data given for different irrigation and fertilizer levels across farms. 2. **Understanding the design:** In a split-plot design, the whole-plot factor (irrigation) is applied to large plots, and the sub-plot factor (fertilizer) is applied within these plots. Replication is across farms. 3. **Data summary:** The data table shows yield (kg/sub-plot) for each combination of irrigation (1 or 2) and fertilizer (1 to 4) across three farms. 4. **Calculate the mean yield for each irrigation and fertilizer combination across farms:** For each row, mean yield = $\frac{\text{Farm A} + \text{Farm B} + \text{Farm C}}{3}$ - Irrigation 1, Fertilizer 1: $\frac{69 + 86 + 88}{3} = \frac{243}{3} = 81$ - Irrigation 1, Fertilizer 2: $\frac{131 + 128 + 108}{3} = \frac{367}{3} \approx 122.33$ - Irrigation 1, Fertilizer 3: $\frac{173 + 180 + 150}{3} = \frac{503}{3} \approx 167.67$ - Irrigation 1, Fertilizer 4: $\frac{219 + 180 + 201}{3} = \frac{600}{3} = 200$ - Irrigation 2, Fertilizer 1: $\frac{136 + 114 + 138}{3} = \frac{388}{3} \approx 129.33$ - Irrigation 2, Fertilizer 2: $\frac{181 + 137 + 151}{3} = \frac{469}{3} \approx 156.33$ - Irrigation 2, Fertilizer 3: $\frac{217 + 196 + 188}{3} = \frac{601}{3} \approx 200.33$ - Irrigation 2, Fertilizer 4: $\frac{208 + 236 + 253}{3} = \frac{697}{3} \approx 232.33$ 5. **Interpretation:** The mean yields increase with fertilizer level and irrigation level, indicating both factors affect yield. 6. **Next steps:** To analyze the effects statistically, one would perform a split-plot ANOVA considering irrigation as the whole-plot factor and fertilizer as the sub-plot factor, with replication across farms. 7. **Summary:** We computed average yields for each treatment combination across farms to understand the data structure and prepare for further statistical analysis.