1. The problem asks to find the error in the sample mean computed in Part A and Part C, given the population mean $\mu = 12.58\%$ and sample means from Part A and Part C. 2. The error in the sample mean is calculated as the difference between the sample mean ($\bar{x}$) and the population mean ($\mu$): $$\text{Error} = \bar{x} - \mu$$ 3. For Part A, the error is given as 1.4, which means: $$\bar{x}_A - 12.58 = 1.4 \implies \bar{x}_A = 12.58 + 1.4 = 13.98\%$$ 4. For Part C, the error is given as 0.1, which means: $$\bar{x}_C - 12.58 = 0.1 \implies \bar{x}_C = 12.58 + 0.1 = 12.68\%$$ 5. Therefore, the errors in the sample means computed in Part A and Part C are 1.4 and 0.1 respectively, representing how much the sample means deviate from the population mean. Final answers: - Error in sample mean (Part A): 1.4 - Error in sample mean (Part C): 0.1