1. **State the problem:** We have hourly rates of 10 high schoolers' part-time jobs and need to find mean, median, and mode for the original data and then after removing the high salary of 50.15. 2. **Original data:** $[12.15, 11.50, 14.50, 12.60, 18.00, 11.50, 12.30, 14.50, 50.15, 11.30]$ 3. **Find the mean (original):** $$\text{mean} = \frac{12.15 + 11.50 + 14.50 + 12.60 + 18.00 + 11.50 + 12.30 + 14.50 + 50.15 + 11.30}{10} = \frac{168.5}{10} = 16.85$$ 4. **Find the median (original):** Sort data: $$[11.30, 11.50, 11.50, 12.15, 12.30, 12.60, 14.50, 14.50, 18.00, 50.15]$$ Median is average of 5th and 6th values: $$\frac{12.30 + 12.60}{2} = 12.45$$ 5. **Find the mode (original):** Values 11.50 and 14.50 both appear twice, so modes are 11.50 and 14.50. 6. **Remove 50.15 and recompute:** New data: $$[12.15, 11.50, 14.50, 12.60, 18.00, 11.50, 12.30, 14.50, 11.30]$$ 7. **Mean (new):** $$\text{mean} = \frac{12.15 + 11.50 + 14.50 + 12.60 + 18.00 + 11.50 + 12.30 + 14.50 + 11.30}{9} = \frac{118.35}{9} \approx 13.15$$ 8. **Median (new):** Sort data: $$[11.30, 11.50, 11.50, 12.15, 12.30, 12.60, 14.50, 14.50, 18.00]$$ Median is 5th value: $$12.30$$ 9. **Mode (new):** 11.50 and 14.50 still appear twice, so modes remain 11.50 and 14.50. 10. **Which statistic changed most?** Mean changed from 16.85 to 13.15 (difference 3.70), median changed from 12.45 to 12.30 (difference 0.15), mode unchanged. **Answer:** Mean was most affected by removing the high salary. **Units:** All answers are in dollars per hour. Final answers: - Original mean: 16.85 dollars per hour - Original median: 12.45 dollars per hour - Original mode: 11.50 and 14.50 dollars per hour - New mean: 13.15 dollars per hour - New median: 12.30 dollars per hour - New mode: 11.50 and 14.50 dollars per hour - Most affected statistic: mean