Resistance Distribution
1. **Problem Statement:** We have a frequency distribution of resistors with their resistances and counts. We need to find:
(i) Modal resistance
(ii) Median resistance
(iii) Mean resistance
(iv) Standard deviation
2. **Given Data:**
| No of resistors (f) | Resistance (x) |
|---------------------|----------------|
| 2 | 112 |
| 8 | 115 |
| 10 | 116 |
| 12 | 108 |
| 14 | 102 |
3. **(i) Modal Resistance:**
The mode is the resistance with the highest frequency.
Here, max frequency is 14 at resistance 102.
**Answer:** Modal resistance = $102\ \Omega$
4. **(ii) Median Resistance:**
- Total number of resistors $N = 2 + 8 + 10 + 12 + 14 = 46$
- Median position = $\frac{N+1}{2} = \frac{46+1}{2} = 23.5^{th}$ value
- Cumulative frequencies:
- 2 (112)
- 2+8=10 (115)
- 10+10=20 (116)
- 20+12=32 (108)
- 32+14=46 (102)
- The 23.5th value lies in the group with resistance 108 (since cumulative frequency reaches 32 here).
**Answer:** Median resistance = $108\ \Omega$
5. **(iii) Mean Resistance:**
Formula: $$\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$$
Calculate $\sum f_i x_i$:
- $2 \times 112 = 224$
- $8 \times 115 = 920$
- $10 \times 116 = 1160$
- $12 \times 108 = 1296$
- $14 \times 102 = 1428$
Sum: $224 + 920 + 1160 + 1296 + 1428 = 5038$
Mean: $$\bar{x} = \frac{5038}{46} \approx 109.52\ \Omega$$
6. **(iv) Standard Deviation:**
Formula: $$\sigma = \sqrt{\frac{\sum f_i (x_i - \bar{x})^2}{\sum f_i}}$$
Calculate each $(x_i - \bar{x})^2$ and multiply by $f_i$:
- For 112: $(112 - 109.52)^2 = 6.1504$, $2 \times 6.1504 = 12.3008$
- For 115: $(115 - 109.52)^2 = 30.1504$, $8 \times 30.1504 = 241.2032$
- For 116: $(116 - 109.52)^2 = 42.1504$, $10 \times 42.1504 = 421.504$
- For 108: $(108 - 109.52)^2 = 2.3104$, $12 \times 2.3104 = 27.7248$
- For 102: $(102 - 109.52)^2 = 56.5504$, $14 \times 56.5504 = 791.7056$
Sum: $12.3008 + 241.2032 + 421.504 + 27.7248 + 791.7056 = 1494.4384$
Standard deviation: $$\sigma = \sqrt{\frac{1494.4384}{46}} = \sqrt{32.4843} \approx 5.70\ \Omega$$
**Final answers:**
- Modal resistance = $102\ \Omega$
- Median resistance = $108\ \Omega$
- Mean resistance = $109.52\ \Omega$
- Standard deviation = $5.70\ \Omega$