1. **Problem Statement:** We have 400 students at Loyola College in 2015. The number of females is 180. The region-wise breakup is given by angles: North = 126°, South = 144°, East and West = 90°. We are asked: If all students who took Maths and Physics weigh less than 40 kg, what percentage of those who weigh less than 40 kg took Chemistry or Economics or History as their main subject? 2. **Understanding the problem:** - Total students = 400 - The pie chart angles for regions sum to 360° (126° + 144° + 90° = 360°), confirming the full distribution. - The question involves subjects and weights, but only the region-wise angles are given. - We assume the subject-wise breakup is known or can be inferred. 3. **Formula and approach:** - The percentage of students in a sector is proportional to the angle of that sector divided by 360°. - Number of students in a sector = (angle/360) × total students. - We know all students who took Maths and Physics weigh less than 40 kg. - We want the percentage of students weighing less than 40 kg who took Chemistry, Economics, or History. 4. **Calculations:** - Total students = 400 - Number of students who took Maths and Physics = $M+P$ (unknown exact number, but all weigh less than 40 kg) - Number of students who weigh less than 40 kg = number who took Maths and Physics + number who took Chemistry, Economics, or History and weigh less than 40 kg. Since only students who took Maths and Physics weigh less than 40 kg, the rest weigh 40 kg or more. Therefore, the students who weigh less than 40 kg are exactly those who took Maths and Physics. Hence, the percentage of those who weigh less than 40 kg and took Chemistry or Economics or History is 0%. 5. **Answer:** None of the given options match 0%, so the problem likely assumes the subject-wise breakup is given but missing here. **Since the problem is incomplete without subject-wise data, we cannot compute the exact percentage.** **Slug:** region breakup **Subject:** statistics