1. The problem asks to find the probability $P(Z > -0.58)$ where $Z$ is a standard normal variable. 2. The standard normal distribution is symmetric about zero, and probabilities are found using the standard normal table which gives $P(Z \leq z)$. 3. We use the complement rule: $$P(Z > -0.58) = 1 - P(Z \leq -0.58)$$ 4. From the standard normal table, $P(Z \leq -0.58) = 0.2810$. 5. Therefore, $$P(Z > -0.58) = 1 - 0.2810 = 0.7190$$. 6. So, the probability that $Z$ is greater than $-0.58$ is $0.7190$ or 71.90%.