1. The problem asks for the probability that a randomly chosen worker spent more than 5 hours but at most 10 hours working from home, i.e., $5 < H \leq 10$. 2. From the cumulative frequency graph, the cumulative frequency at $H=5$ hours is approximately 10 workers. 3. The cumulative frequency at $H=10$ hours is approximately 20 workers. 4. The number of workers who spent between 5 and 10 hours working from home is the difference between these cumulative frequencies: $$20 - 10 = 10$$ 5. Since there are 60 workers in total, the probability is: $$\frac{10}{60} = \frac{1}{6} \approx 0.1667$$ 6. Therefore, the probability that $5 < H \leq 10$ is $\frac{1}{6}$ or approximately 0.1667.