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Normal Probability 96F712

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Normal Probability 96F712


1. The problem asks to find the probability that a standard normal random variable $Z$ is less than 2.4, i.e., $P(Z < 2.4)$. 2. We use the standard normal distribution table or a calculator to find this probability. The standard normal distribution has mean 0 and standard deviation 1. 3. The cumulative distribution function (CDF) for the standard normal variable $Z$ is $\Phi(z) = P(Z \leq z)$. We want $\Phi(2.4)$. 4. Looking up $z=2.4$ in the standard normal table or using a calculator, we find $\Phi(2.4) \approx 0.9918$. 5. This means there is approximately a 99.18% chance that $Z$ is less than 2.4. Final answer: $$P(Z < 2.4) = 0.9918$$