1. **Problem Statement:** We have a normal distribution with mean $m = 23.6$ kg and standard deviation $\sigma = 1.8$ kg. 2. **Understanding the Normal Distribution:** The normal distribution is symmetric and bell-shaped, centered at the mean $m$. The standard deviation $\sigma$ measures the spread of the data. 3. **Given Data:** - Mean $m = 23.6$ kg - Standard deviation $\sigma = 1.8$ kg - The shaded area is between $21.8$ kg and $25.4$ kg. 4. **Calculate the Z-scores for the bounds:** The Z-score formula is: $$Z = \frac{X - m}{\sigma}$$ Calculate for $21.8$ kg: $$Z_1 = \frac{21.8 - 23.6}{1.8} = \frac{-1.8}{1.8} = -1$$ Calculate for $25.4$ kg: $$Z_2 = \frac{25.4 - 23.6}{1.8} = \frac{1.8}{1.8} = 1$$ 5. **Interpretation:** The shaded area corresponds to the probability that a value lies within $\pm 1$ standard deviation from the mean. 6. **Using the Empirical Rule:** - About 68% of data lies within $\pm 1\sigma$ of the mean. 7. **Final Answer:** The shaded area under the curve between $21.8$ kg and $25.4$ kg represents approximately 68% of the data in this normal distribution.