1. The problem asks to find 2 values to complete a two-way table showing no association between returning to play in less than 2 days and the treatment (ice or heat). 2. To show no association, the proportion of players returning in less than 2 days should be the same for both treatments. 3. Suppose the total number of players receiving ice treatment is $N_{ice}$ and heat treatment is $N_{heat}$. 4. Let $x$ be the number of players returning in less than 2 days with ice, and $y$ be the number with heat. 5. For no association, the proportion must be equal: $$\frac{x}{N_{ice}} = \frac{y}{N_{heat}}$$ 6. Choose $x$ and $y$ to satisfy this equality based on the totals in the table. 7. For example, if $N_{ice} = 10$ and $N_{heat} = 20$, then $x = 5$ and $y = 10$ would show no association. 8. For the second question, the 2 values showing no association are easier to choose because they follow a simple proportional relationship. 9. Values showing association require more complex differences in proportions, making them harder to select. Final answer: The 2 values must satisfy $$\frac{x}{N_{ice}} = \frac{y}{N_{heat}}$$ to show no association.