1. **Stating the problem:** We are given a frequency distribution of time intervals (in minutes) between placing an order and its delivery for a wholesaler. We need to find the mode of this time. 2. **Data given:** Time intervals (minutes): 20-25, 25-30, 30-35, 35-40, 40-45, 45-50, 50-55 Number of orders (frequency): 2, 5, 5, 6, 7, (missing), (missing) Note: The frequencies for 45-50 and 50-55 are missing in the problem statement. Assuming the problem intends only the first five intervals with frequencies 2, 5, 5, 6, 7. 3. **Finding the mode:** The mode is the value corresponding to the highest frequency. Frequencies: 2, 5, 5, 6, 7 Highest frequency = 7 corresponding to class interval 40-45. 4. **Mode formula for grouped data:** $$\text{Mode} = L + \left(\frac{f_1 - f_0}{2f_1 - f_0 - f_2}\right) \times h$$ where: - $L$ = lower boundary of modal class = 40 - $f_1$ = frequency of modal class = 7 - $f_0$ = frequency of class before modal class = 6 - $f_2$ = frequency of class after modal class = 0 (since no data given, assume 0) - $h$ = class width = 5 5. **Calculate mode:** $$\text{Mode} = 40 + \left(\frac{7 - 6}{2 \times 7 - 6 - 0}\right) \times 5 = 40 + \left(\frac{1}{14 - 6}\right) \times 5 = 40 + \frac{1}{8} \times 5 = 40 + 0.625 = 40.625$$ 6. **Final answer:** The mode of the time is approximately **40.63 minutes**. (Note: The provided answer in the question is Mo=38.78, which suggests different frequencies or data. Based on given data, this is the calculated mode.)